Latest Updated : November 2023

If you are in search of **NCERT solutions for Class 8 Maths Chapter** **7 Comparing Quantities**, then you are at the right place. When it comes to **Mathematics**, it is a subject that holds value for students across various academic streams, be it science, biology, or commerce and having a very good understanding of basic math concepts will help you in achieving your goal and make it much more easier.

Here we provide detailed **NCERT solutions for Class 8 Maths**Â of all the chapters,Â **exercise wise**Â withÂ **updated syllabus by NCERT**. These NCERT solutions for Class 8 Maths have been carefully crafted to provide detailed explanations, ensuring that students can grasp the concepts effectively. We also provide extra practice questions for the same, so feel free to bookmarkÂ **ncertforclass8.com**Â to boost your preparation.

## NCERT Solutions for Class 8 Maths Chapter 7 Comparing Quantities Ex 7.2

**Class 8 Maths Chapter** 7 Comparing Quantities **Exercise 7.**2

**Exercise 7.2**

**1. During a sale, a shop offered a discount of 10% on the marked prices of all the items. What would a customer have to pay for a pair of jeans marked at â‚¹1450 and two shirts marked at â‚¹ 850 each?**

Solution:

Rate of discount on all items = 10%

Marked Price of a pair of jeans =â‚¹ 1450

Marked Price of a shirt =â‚¹ 850

`\[Discount\ on\ a\ pair\ of\ jeans=\frac{\left(Rate\ \times Marked\ price\right)}{100}=\frac{\left(10\ \times1450\right)}{100}=\ â‚¹145\]`

`\[S.P.\ of\ a\ pair\ of\ jeans=â‚¹\ 1450-â‚¹145\ \ =â‚¹1305\]`

`\[Marked\ \Pr ice\ of\ two\ shirts=2\times\ 850=â‚¹1700\]`

`\[Discount\ on\ two\ shirts=\frac{\left(Rate\ \times Marked\ price\right)}{100}=\frac{\left(10\ \times1700\right)}{100}=\ â‚¹170\]`

`\[S.P.\ of\ two\ shirts\ =\ â‚¹1700-â‚¹170\ =\ â‚¹1530\]`

Therefore, the customer had to pay =â‚¹ 1305 + â‚¹ 1530 = â‚¹ 2,835

**2. The price of a TV is â‚¹ 13,000. The sales tax charged on it is at the rate of 12%. Find the amount that Vinod will have to pay if he buys it.**

Solution:

C.P. = â‚¹13,000 and Sale tax rate = 12%

Let C.P. be 100, then S.P. for purchaser = 100+12= â‚¹112

When C.P. is â‚¹100, then S.P. = â‚¹112

`\[âˆ´\ When\ CP\ =\ â‚¹1\ ,\ then\ S.P\ =\ \frac{112}{100}\]`

`\[âˆ´\ When\ C.P\ =\ â‚¹13,000,\ then\ S.P=\ \frac{112}{100}\ \times\ 13,000=\ â‚¹14,560\]`

**3. Arun bought a pair of skates at a sale where the discount given was 20%. If the amount he pays is â‚¹1,600, find the marked price.**

Solution:

S.P. = â‚¹1,600

Rate of discount = 20%

Let M.P. be â‚¹100, then S.P. for customer = 100 – 20 = â‚¹80

When S.P. is â‚¹80, then M.P. = â‚¹100

`\[âˆ´\ When\ S.P\ is\ â‚¹1\ ,\ then\ M.P\ =\ \frac{100}{80}\]`

`\[âˆ´\ When\ S.P\ is\ â‚¹1600\ then\ M.P\ =\ \frac{100}{80}\times1600=\ â‚¹\ 2,000\]`

**4. I purchased a hair-dryer for â‚¹ 5,400 including 8% VAT. Find the price before VAT was added.**

Solution:

C.P. = â‚¹ 5,400

Rate of VAT = 8%

Let C.P. without VAT is â‚¹100, then price including VAT = 100 + 8 = â‚¹108

When price including VAT is â‚¹108, then original price = â‚¹100

`\[âˆ´\ When\ price\ including\ VAT\ is\ \ â‚¹1,\ then\ original\ \ price=\frac{100}{108}\]`

`\[âˆ´\ When\ price\ including\ VAT\ is\ \ â‚¹5400,\ then\ original\ \ price=\frac{100}{108}\ \times\ 5400=\ â‚¹5,000.\]`

**5. An article was purchased for â‚¹ 1239 including GST of 18%. Find the price of the article before GST was added?**

Solution:

Let the cost price of article without GST = â‚¹ 100

GST = 18%

So, total cost including GST = 100+ 18 = â‚¹118

âˆ´ When total cost is â‚¹118, then actual cost = â‚¹ 100

`\[âˆ´\ \ When\ total\ \cos t\ is\ â‚¹1,\ \ then\ \ actual\ \cos t\ =\frac{100}{118}\]`

`\[âˆ´\ \ When\ total\ \cos t\ is\ â‚¹1239,\ \ then\ \ actual\ \cos t\ =\frac{100}{118}\ \times1239\ =â‚¹\ 1,050\]`

So, the price of the article before GST was â‚¹1050.

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