Latest Updated : November 2023

If you are in search of **NCERT solutions for Class 8 Maths Chapter 10 Exponents and Powers**, then you are at the right place. When it comes to **Mathematics**, it is a subject that holds value for students across various academic streams, be it science, biology, or commerce and having a very good understanding of basic math concepts will help you in achieving your goal and make it much more easier.

Here we provide detailed **NCERT solutions for Class 8 Maths** of all the chapters, **exercise wise** with **updated syllabus by NCERT**. These NCERT solutions for Class 8 Maths have been carefully crafted to provide detailed explanations, ensuring that students can grasp the concepts effectively. We also provide extra practice questions for the same, so feel free to bookmark **ncertforclass8.com** to boost your preparation.

## NCERT Solutions for Class 8 Maths Chapter 10 Exponents and Powers Ex 10.2

**Class 8 Maths Chapter** **10 Exponents and Powers** **Exercise 10.2**

**Exercise 10.2**

**1. Express the following numbers in standard form.(i) 0.0000000000085 **

**(ii) 0.00000000000942**

**(iii) 6020000000000000 **

**(iv) 0.00000000837**

**(v) 31860000000**

Solution-

`\[(i)\ 0.0000000000085=0.0000000000085\times\frac{10^{12}}{10^{12}}=8.5\times10^{-12}\]`

`\[(ii)\ 0.00000000000942=0.00000000000942\times\frac{10^{12}}{10^{12}}=9.42\times10^{-12}\]`

`\[(iii)\ 6020000000000000=6020000000000000\times\frac{10^{15}}{10^{15}}=6.02\times10^{15}\]`

`\[(iv)\ 0.00000000837=0.00000000837\times\frac{10^9}{10^9}=8.37\times10^{-9}\]`

`\[(v)\ 31860000000=31860000000\times\frac{10^{10}}{10^{10}}=3.186\times10^{10}\]`

**2. Express the following numbers in usual form.**

`\[(i)\ 3.02\times10^{-6}\]`

`\[(ii)\ 4.5\times10^4\]`

`\[(iii)\ 3\times10^{-8}\]`

`\[(iv)1.0001\times10^9\]`

`\[(v)\ 5.8\times10^{12}\]`

`\[(vi)\ 3.61492\times10^6\]`

Solution-

`\[(i)\ 3.02\times10^{-6}=\ \frac{3.02}{10^6}=0.00000302\]`

`\[(ii)\ 4.5\times10^4=4.5\times10000=45000\]`

`\[(iii)\ 3\times10^{-8}=\frac{3}{10^8}=0.00000003\]`

`\[(iv)\ 1.0001\times10^9=1000100000\]`

`\[(v)\ 5.8\times10^{12}=5.8\times1000000000000=5800000000000\]`

`\[(vi)\ 3.61492\times10^6=3.61492\times1000000=3614920\]`

**3. Express the number appearing in the following statements in standard form.**

**(i) 1 micron is equal to 1/1000000 m.(ii) Charge of an electron is 0.000,000,000,000,000,000,16 coulomb.(iii) Size of a bacteria is 0.0000005 m(iv) Size of a plant cell is 0.00001275 m(v) Thickness of a thick paper is 0.07 mm**

Solution-

`\[\left(i\right)\ 1micron\ =\frac{1}{10^6}=1\times10^{-6}\]`

`\[\left(ii\right)\ Ch\arg e\ of\ an\ electron=\ 0.00000000000000000016\times\frac{10^{19}}{10^{19}}=1.6\times10^{-19}\ coulomb\]`

`\[\left(iii\right)\ Size\ of\ a\ bacteria=\frac{5}{10000000}=\frac{5}{10^7}=5\times10^{-7}\ m\]`

`\[\left(iv\right)\ Size\ of\ a\ plant\ cell=\ 0.00001275\times\frac{10^5}{10^5}=1.275\times10^{-5}\ m\]`

`\[\left(v\right)Thickness\ of\ a\ thick\ paper=\ 0.07mm=\frac{7}{100}\ mm=\frac{7}{10^2}=7\times10^{-2}\ mm\]`

**4. In a stack there are 5 books each of thickness 20mm and 5 paper sheets each of thickness 0.016 mm. What is the total thickness of the stack.**

Solution-

Thickness of one book = 20 mm

Thickness of 5 books = 20×5 = 100 mm

Thickness of one paper = 0.016 mm

Thickness of 5 papers = 0.016×5 = 0.08 mm

Total thickness of a stack = 100+0.08 = 100.08 mm

`\[=100.08\times\frac{10^2}{10^2}\ mm\]`

`\[=1.0008\ \times10^{2\ }mm\]`

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